What is an equation of the line, in slope intercept form, that passes through the given point and has the given slope? point: (11,3); slope: 4/11

answer: y - 3 = 4/11(x - 11)

step-by-step explanation:

the equation of a straight line can be represented in the point slope form as

y - y1 = m( x - x1)

where

m = slope = (change in the value of y in the vertical axis) / (change in the value of x in the horizontal axis)

the given slope of the line is 4/11 and the point through which the line passes is (11,3)

we would substitute m = 4/11, x1 = 11 and y1 = 3 into y - y1 = m( x - x1) to get the equation in the point slope form. it becomes

y - 3 = 4/11(x - 11)

for the slope intercept form, the equation is y = mx + c

where c is the intercept. to find c, we will substitute

m = 4/11, x = 11 and y = 3 into y = mx + c. it becomes

3 = 4/11 × 11 + c

3 = 4 + c

c = 3 - 4 = -1

the equation becomes

y = 4x/11 - 1

i have no idea just need points sorry

step-by-step explanation:

i think its doubled. let me know

step-by-step explanation: