Solve for z.
in 63 = in z + in 7

ln z + ln 7 = ln 63

When adding two logarithms of the same base, you can combine them into a single logarithm where the input is the product of both previous inputs

ln 7z = ln 63

Take the exponential of e to both sides

7z = 63

Divide both sides by 7

z = 9

Let me know if you need any clarifications, thanks!

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