Net of cuboid having lengh, breadth and height 5,4 and 3 find the area of all faces

The area of all faces of the cuboid is 94 square units

Step-by-step explanation:

Given:

Length = 5

Breadth = 4

Height = 3

To Find :

The area of all faces = ?

Solution:

The area of all the faces  =  surface area of the cuboid

The surface area of the cuboid  =  2(LB + BH + HL)

where

L is the length

B is the breadth

H is the height

Now substituting the values,

The surface area of the cuboid

=>

=>

=>

=>94 square units

the solution is 12x-6y