Find the lengths of the base of a triangle when one side is 2 cm shorter than the base and the other side is 3 cm longer than the base. the perimeter is greater than 19 cm

The length of base of triangle must be greater than 6 cm

Solution:

Let "b" be the base of triangle

Let "a" and "c" be the two sides of triangle

Given that one side is 2 cm shorter than the base

one side = 2 cm shorter than base

a = b - 2   eqn 1

Also given that other side is 3 cm longer than the base

other side = 3 cm longer than the base

c = 3 + b eqn 2

The perimeter of triangle is given as:

P = a + b + c eqn 3

Given that perimeter is greater than 19 cm

P > 19

Substitute eqn 1 and eqn 2 in eqn 3

b - 2 + b + 3 + b > 19

3b + 1 > 19

3b > 19 - 1

3b > 18

Divide both sides by 3

b > 6

Thus length of base of triangle must be b > 6 cm

answer: a) (0,0), (1,1), (2,8), and (3,27).

step-by-step explanation:

0^3=0

1^3=1

2^3=8

3^3=27

in effect, the exponential equation for this would me y=3^x. each x-coordinate cubed is giving the y coordinate, so a is your answer : )

x > 1.3

step by step:

8.5−0.9x> 9.8−1.9x

step 1: simplify both sides of the inequality.

−0.9x+8.5> −1.9x+9.8

step 2: add 1.9x to both sides.

−0.9x+8.5+1.9x> −1.9x+9.8+1.9x

1x+8.5> 9.8

step 3: subtract 8.5 from both sides.

1x+8.5−8.5> 9.8−8.5

1x> 1.3

step 4: divide both sides by 1.

1x/1 > 1.3/1