In a certain algebra 2 class of 25 students, 13 of them play basketball and 11 of them play baseball. there are 4 students who play neither sport. what is the probability that a student chosen randomly from the class plays both basketball and baseball?

Step-by-step explanation:

Given: There are 2 classes of 25 students.

            13 play basketball

            11 play baseball.

            4 play neither of sports.

Lets assume basketball as "a" and baseball as "b".

We know, probablity dependent formula; P(a∪b)= P(a)+P(b)-p(a∩b)

As given total number of student is 25

Now, subtituting the values in the formula.

⇒P(a∪b)=

taking LCD as 25 to solve.

⇒P(a∪b)=

∴ P(a∪b)=

Hence, the probability that a student chosen randomly from the class plays both basketball and baseball is .

207/8 is the right

answer: entity is prob the answer

step-by-step explanation: