Solve 8 = 2^x+4

x=-4
x=-1
x=0
x=7

show step by step or proof

Step-by-step explanation:

To solve the problem as written, subtract 4, then take the logarithm base 2.

  4 = 2^x

  2^2 = 2^x

  2 = x . . . . . . logarithm base 2

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Because this is not an answer choice, we suspect your problem is really ...

  8 = 2^(x+4) . . . . . . parentheses are required

  2^3 = 2^(x+4) . . . . show 8 as a power of 2

  3 = x+4 . . . . . . . . . take the log to the base 2 (equate exponents)

  -1 = x . . . . . . . . . . . subtract 4