Find two consecutive even numbers such that the difference of one-half the larger number and two-fifths the smaller number is equal to five. 38 and 40 40 and 42 42 and 44

The two consecutive even numbers are 40 and 42

Solution:

Let the two consecutive even numbers be x and x + 2

Let "x" be the smaller number and "x + 2" be the larger number

Given that difference of one-half the larger number and two-fifths the smaller number is equal to five

So we can frame a equation as,

one-half the larger number - two-fifths the smaller number = 5

Thus x = 40

And x + 2 = 40 + 2 = 42

Thus the two consecutive even numbers are 40 and 42

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