What is the equation of a line that is parallel to y=3/5x−7 and passes through (15, 8) ?

enter your answer in the box.

y=3/5x - 14

Step-by-step explanation:

y=35x−8 ; (−15,−23)

Rewrite in slope-intercept form.

y=35x−8

Using the slope-intercept form, the slope is 35

.

m=35

To find an equation that is parallel to y=35x−8

, the slopes must be equal. Using the slope of the equation, find the parallel line using the point-slope formula.

(−15,−23)

m=35

Using the point-slope form y−y1=m(x−x1)

, plug in m=35, x1=−15, and y1=−23

.

y−(−23)=35⋅(x−(−15))

Simplify to get the point-slope formula.

y+23=35(x+15)

Solve for y

.

y=35x−14