Given a quadrilateral with vertices , 5), , 5), , 0), and h(−2, 0):
a. prove quadrilateral is a parallelogram.
b. prove (2, 2.5) is a point on both diagonals of the quadrilateral

cant help when you put question marks!

please do this better!

80° is the measure of gh

step-by-step explanation:

circle f is congruent to circle j

we have two circle with center f and j.

both circles are congruent. the radius of the circle would be equal.

see the attachment for the circle.

we are given ∠efd ≅ ∠gjh

therefore, arc (ed) = arc (gh)     (∴ circle f is congruent to circle j)

but ∠dfe=80°=arc (ed)

therefore, arc (gh) = 80°

thus, 80° is the measure of gh

i dont know what you want me to answer for this but im guessing 2: 11?