Two planes leave an airport at the same time, one traveling east at 250 miles/hr and the other traveling southwest at 300 miles/hr. how far apart are they after 3 hours?

They would be 1525.48 miles apart.

Step-by-step explanation:

Given,

Speed of first plane = 250 miles/hr,

∵ Distance = speed × time,

So, the distance covered by the plane after 3 hours = 250 × 3 = 750 miles,

Similarly, speed of second plane = 300 miles/hr,

Distance covered by the plane after 3 hours = 300 × 3 = 900 miles,

Now, first plane is going east direction while other one is going towards southwest  direction,

That is, the angle between them = 90° + 45° = 135°,

if x be the distance between them after 3 hours,

Using cosine law,

Hence, they would be 1525.48 miles apart after 3 hours.

answer: -0.5 would be the most likley outcome

step-by-step explanation:

d. 145*2 is 290 than the total angle is 360 then minus 290 then divide by two