If street lights are placed at most 150 feet apart, how many street lights will be needed for a street that is 2 miles long, assuming that there are lights at each end of the street?

We need 741 street lights for a street that is 2 miles long .

Step-by-step explanation:

We know that 1 mile = 5280 feet

Then, 2 miles = 2 x 5280 = 10560 feet

Given : Street lights are placed at most 150 feet apart.

Then, the number of intervals in 2 miles long street = 2 miles ÷ 150

=(10560 feet)  ÷ 150

= 70.4 ≈ 70  [The distance between streets cannot be greater than 150 feet.]

If there are lights at each end of the street , then we need to starts from one end .

Total lights = Number of interval +1

=70+1  =71

Hence, we need 741 street lights for a street that is 2 miles long .

step-by-step explanation:

de-gf

hj=3x+20

ji=15x-64

vertical asymptote .

horizontal asymptote .

step-by-step explanation:

given function is .

vertical asymptote is given by setting

denominator =0

when degree of numerator and denominator are same then divide first term of numerator by first term of denominator to get horizontal asymptote.