Write a system of linear equations in which (2,-1) is a solution of equation one but not a solution of equation 2, and (5,5) is a solution of the system

x equals 1

step-by-step explanation:

f(4)=f(×)

x=1

answer: (c) m∠qpo + (2x + 16)° = 180°

step-by-step explanation:

the opposite angles of a quadrilateral are supplementary.

so, ∠o + ∠q = 180°   and   ∠p + ∠r = 180°

since ∠r = 2x + 16°, we can use substitution as follows:

∠p + ∠r = 180°

∠p + (2x + 16)° = 180°