3. eighty percent of the dogs at a local kennel are in good health. if the events "a randomly selected dog at this kennel is in good health" and "a randomly selected dog at this kennel
weighs more than 30 pounds" are independent, what do you know about the probability that a randomly selected dog that weighs more than 30 pounds will be in good health?
justify your answer.

80% or 0.80

Step-by-step explanation:

Data provided in the question:

Probability that the dogs at a local kennel are in good health = 80% = 0.80

Since, Both the events are independent

Therefore,

The event that is selected dog weighs more than 30 pounds.

This will not change the  probability of the independent event

Hence,

The probability that a randomly selected dog that weighs more than 30 pounds will be in good health will also be 80% or 0.80

michael scott & dwight schrute

step-by-step explanation:

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see explanation

step-by-step explanation:

since the sequence is geometric there is a common ratio r between consecutive terms, that is

r = 4 ÷ - 2 = - 2

r = - 8 ÷ 4 = - 2

r = 16 ÷ 8 = - 2

the next term - 13 must be incorrect as it should be - 32 for the sequence to be geometric.

the first 4 terms are therefore geometric with common ratio r = - 2