2. confirm that the mean for group a is 6.76 ounces, and calculate the mean for group b.

Mean of weights for Group A = 6.76

Mean of weights for Group B =6.48

Missing Portion:

The 10 tomatoes with their weights shown. They have been ordered from largest to smallest based on weight.

Imagine that someone assisting you uses a random-number generator or some other impartial  selection device and randomly selects Tomatoes number 1, 4, 5, 7, and 10 to be in Group A.

Step-by-step explanation:

So, by default, Tomatoes number 2, 3, 6, 8, and 9 will be in Group B.

Weights of tomatoes in group Group A :

9.1 , 7.7, 7.3 , 5.9, 3.8

Weights of tomatoes in group Group B :

8.4, 8, 6.4, 5.2, 4.4

Mean of weights for Group A = = 6.76 ounces

Mean of weights for Group B = = 6.48 ounces

Which confirms mean for group A is 6.76 ounces and gives us mean of Group B as 6.48 ounces

solution:

as, mean is defined as sum of all the observations divided by total number of observations.

and , median is mid value of the data whether arranged in ascending order or descending order.

consider, roadsters:

2,3,4,5,6,7,8,9

mean =

also, median= , because number of observations is even, so median is mean of two mid values.

now, coming to bandits

2,3,4,5,6

mean =  

median = 4, as number of observations is odd.

so, roadsters has greater median as well mean than bandits.

→option a is true about the repairs performed on 2 types of cars:

bandits have lower median and mean than roadsters.

exactly you go it

step-by-step explanation: