2. a traveler estimates that, for an upcoming trip, the probability of catching malaria is 0.18, the probability of catching typhoid is 0.13, and the probability of catching neither
of the two diseases is 0.75.
a. draw a venn diagram to represent this information.
b. calculate the probability of catching both of the diseases.
c. are the events "catches malaria" and "catches typhoid" independent? explain your answer

a. Venn diagram is explained in the attached word file

b. 0.06

c. Not independent

Step-by-step explanation:

a. The attached word file explain the probabilities of catching malaria and typhoid using the Venn diagram

b. Probability of catching both diseases=P(M and T)=P(M∩T)=?

using the addition rule

P(MUT)=P(M)+P(T)-P(M∩T)

P(M)=0.18

P(T)=0.13

P(MUT)=P(M or T)=1-P(neither M nor T)=1-0.75=0.25

P(MUT)=P(M)+P(T)-P(M∩T)

0.25=0.18+0.13-P(M∩T)

P(M∩T)=0.18+0.13-0.25=0.06

c.  The two variables are independent if P(M∩T)=P(M)*P(T)

P(M∩T)=0.06

P(M)*P(T)=0.18*0.13=0.023

So, the events catching malaria and typhoid is dependent.

see below

step-by-step explanation:

7.   there are 10 data points in the set.   the middle point is between 5 and 6.   the middle point in the top half is 8   and the middle point in the bottom half is 3. to find the iqr , take point 8 and subtract point 3

mid term   point 8 = 100   point 3 = 88

iqr = 100-88 = 12

final   point 8 = 93   point 3 = 78

iqr = 93 - 78 = 15

the final has the greatest iqr

6.   b - there is a high data value that causes the data set to be asymmetrical for the males: the data for males are high and asymmetrical .   there is an outlier for the males that skews the data

5.   the   iqr is a better measure of spread for the movies and basketball games.   since the basketball game has an outlier, we do not want to use standard deviation for measurement.  

3.   the exam median is much higher than the class median.   the median line is farther to the right on the exams

2.   there is no way to tell what the means are from the box and whisker plots.