13. six musicians will play in a recital. three will perform before intermission, and three will perform after intermission. how many different ways are there to choose which three musicians
will play before intermission? is this question answered by considering permutations or combinations? explain.

20 ways

Step-by-step explanation:

Given that six musicians will play in a recital. Three will perform before intermission, and three will perform after intermission

Since A singing first and B second is different from B first and A second, here order matters.  So permutation

But selecting 3 members from 6 for the period before intermission is combination.

Thus 3 players selected in 6C3 ways = 20 ways

Once these 3 players are selected other three are fixed.

Total number of ways of  choose which three musicians

will play before intermission = combination = 6C3 *1 = 20 ways

  n=   0.0000 - 0.3750 i  

  n=   0.0000 + 0.3750 i

step-by-step explanation:

one of these should be correct