Given cos0 = -2/3 and lies in quadrant lll what is the exact value of sin 0 in simplified form ?
show all work

  sin(θ) = -(√5)/3

Step-by-step explanation:

In quadrant III, both sine and cosine are negative. Then the value of interest is ...

  sin(θ) = -√(1 - cos(θ)²) = -√(1 -4/9)

  sin(θ) = -(√5)/3

you probably already have the answer but anyways it's b. 15.0

step-by-step explanation:

look at the picture.

y-intercept for the function on a picture is 4 → point (0, 4).

y-intercept for the function

is for x = 0. substitute:

y-intercept is 8 → point (0, 8).