![[2(\cos15+i15)^{4}]\\=2^{4}(\cos15+i\sin15)^{4}\\=16(\cos15+i\sin15)^{4}..........(1)](/tpl/images/0448/9187/3c20d.png)
![[2(\cos15+i\sin15)]^{4}=16\times \frac{1+\sqrt{3}i}{2} =8+8\sqrt{3}i](/tpl/images/0448/9187/b125d.png)
[2(cos15° + isin15°)]^4
16 + 16 square rt 3 i
8 + 8square rt 3 i
16 square rt 3...
Mathematics, 09.01.2020 23:31 ziggyrules2002
[2(cos15° + isin15°)]^4
16 + 16 square rt 3 i
8 + 8square rt 3 i
16 square rt 3 + 16i
8 square rt 3 + 8i
Answers: 1
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