An office building has two elevators. one elevator starts out on the 4th floor, 35 feet above the ground, as it’s defending at a rate of 2.2 feet per second. the other elevator starts out at ground level and is rising at a rate of 1.7 feet per second. write a system of equations to represent the situation

The system of equations are y = 35 - 2.2x and y = 1.7x

Solution:

Given that, office building has two elevators.

One elevator starts out on the 4th floor, 35 feet above the ground, as it’s descending at a rate of 2.2 feet per second

Let "x" be the number of seconds for which the elevator is descending

Therefore, for "x" seconds the descended feet is 2.2x feet

The elevator is at 4 th floor, 35 feet above ground

Therefore, from 35 feet, the elevator has descended 2.2x feet for "x" seconds

Let "y" be the final position of elevator after "x" seconds

Therefore,

y = 35 - 2.2x

The other elevator starts out at ground level and is rising at a rate of 1.7 feet per second

Here, the elevator is rising at a rate of 1.7 feet per second

Therefore, for "x" seconds, the elevator has raised 1.7x feet

Here the elevator is at ground level, therefore

y = 1.7x

Thus the system of equations are y = 35 - 2.2x and y = 1.7x

the required function is .

step-by-step explanation:

from the given table it is noticed that the graph passing through (-3,7), (0,4), (3,1) and (8,-4).

it is a linear function because the value of y is decrease by one as the value of x increase by 1.

the slope of the function is

the slope of the function is -1 and the y-intercept is 4.

the slope intercept form is

where, m is slope and b is y-intercept.

therefore the required function is . the graph of this function is shown below.

option 2 is correct.

step-by-step explanation:

we are given two inequality equation

x+y> 5 and -3x+2y< -2

first we draw the graph of both function using t-table method

equation: x+y> 5

for x=0, y=5

for x=-5, y=0

table:

x   :   0     5

y   :   5     0

test point (0,0) , 0> 5

false

equation: -3x+2y< -2

for x=0, y=-1

for x=2, y=4

table:

x   :   0     2

y   : -1       4

test point (0,0) , 0< -2

true

now we draw the graph. see the attachment for graph.

common region would be solution set.

option 2 is correct.