At mike’s favorite coffee shop, the coffee of the day is either a dark roast, a medium roast, or a light roast. from past experience, mike knows that the probability of the coffee being a light roast is 0.15 and the probability of the coffee being a dark roast is 0.25. what is the probability of the coffee of the day not being a light roast or a dark roast on the next day that mike visits the coffee shop?

Step-by-step explanation:

Given

Probability that coffee being a light roast is P(1)=0.15

Probability that coffee being a dark roast is P(2)=0.25

considering the event being independent of each other

Probability that coffee not being a light roast or dark roast is given by

P(not being dark or light roast)=1-P(1)-P(2)

P(not being dark or light roast)=1-0.15-0.25

P(not being dark or light roast)=0.6

(1,4) is on graph of f(x)

f(1) = 4

so 1/4 f(x)

1/4 f(1)

1/4. ×4

1

so point for function 1/4. f(x) is (1,1)

step-by-step explanation:

there is a formula i can give you:

it is r^2*n*sin(360/n) divided by 2 where r represents the "radius" and n is the number of sides.

plug them in:

(10sqrt(3))^2*6*sin(360/6) divided by 2

100*3*6*sin(60) divided by 2

900*sin(60)

900*sqrt(3)/2

450*sqrt(3)

approx is 779.4 cm^2