Mathematics, 11.01.2020 09:31 samueltaye

Acar's rear windshield wiper rotates 140°. the total length of the wiper mechanism is 24 inches and the length of the wiper blade is 13 inches. find the area wiped by the wiper blade.

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Answer from: kelchalyssa

The area wiped by the wiper blade is $177\pi$

Step-by-step explanation:

Given:

car's rear windshield wiper rotates = 140°

Total length of the wiper mechanism = 24 inches

Length of the wiper blade = 13 inches

To Find:

The area wiped by the wiper blade = ?

Solution:

The length of the wiper mechanism , r_1 = 24

The length of the wiper mechanism , r_2 = 13

Now arc radius

r_1-r_2 = 24-13 = 11

The wipe rotates 140 degrees

Step 1: converting degree into radians

$\theta = 140 \times \frac{\pi}{180}$

$\theta =\frac{7\pi}{9}$

Step 2: Finding the area of the sector of the circle with radius r_1

The area of the sector

= $\frac{1}{2}r_1 ^2\theta$

= $\frac{1}{2}24^2\times \frac{7\pi}{9}$

= $\frac{576}{2} \times \frac{7\pi}{9}$

= $\frac{4032 \pi}{18}$ ---------------------------(1)

Step 2: Finding the area of the sector with radius r_2

= $\frac{1}{2}r_1 ^2\theta$

= $\frac{1}{2}11^2\times \frac{7\pi}{9}$

= $\frac{121}{2} \times \frac{7\pi}{9}$

= $\frac{1183 \pi}{18}$ ---------------------------(2)

Step 3: Finding the area wiped by the wiper

The area wiped by the wiper = the area of the sector of the circle with radius r_1 - the area of the sector with radius r_2

From(1) and(2)

The area wiped by the wiper = $\frac{4032 \pi}{18}$ - $\frac{847\pi}{18}$

The area wiped by the wiper = $\frac{3185\pi}{18}$

The area wiped by the wiper = $177\pi$

Answer from: Quest

Im not that good with division but i think 5 is -6but dont quote me on thatim not the best in division but thats my answer

Answer from: Quest

the results from a pre-test for students for the year 2000 and the year 2010 are illustrated in the box plot. what do these results tell us about how students performed on the 29 question pre-test for the two years?

if we compare only the lowest and highest scores between the two years, we might conclude that the students in 2010 did better than the students in 2010. this conclusion seems to follow since the lowest score of 8 in 2010 is greater in value than the lowest score of 6 in 2000. also, the highest score of 28 in 2010 is greater in value than the highest score of 27 in 2000.

but the box portion of the illustration gives us more detailed information. the middle bar in each box shows us that the median score of 20 in 2000 is greater in value than the median score of 17 in 2010. further, we note that the box and whiskers divide the illustration into four pieces. each of these four pieces represents the same portion of students. so, the upper half of the students in 2000 scored in the same score range as the upper one-fourth of the students in 2010, see the illustration at a score of 20.

by considering the upper one-fourth, upper half, and upper three-fourths instead of just the lowest and highest scores, we would conclude that the students as a whole did much better in 2000 than in 2010. we would conclude that as a whole the students in 2010 are less prepared than the students in 2000.

in this section, we discuss box-and-whisker plots and the five key values used in constructing a box-and-whisker plot. the key values are called a five-number summary, which consists of the minimum, first quartile, median, third quartile, and maximum.

step-by-step explanation:

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Acar's rear windshield wiper rotates 140°. the total length of the wiper mechanism is 24 inches and...

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