Three consecutive odd integers have a sum of 45

13, 15, and 17

Step-by-step explanation: This problem states that the sum of 3 consecutive odd integers is 45 and it asks us to find the integers.

3 consecutive odd integers are represented as follows.

X ⇒ first integer

X + 2 ⇒ second integer

X + 4 ⇒ third integer

Since the sum of these is 45, our equation reads X + X + 2 + X + 4 = 45.

Simplifying on the left, we get 3x + 6 = 45. Subtract 6 from both sides of the equation to get 3x = 39 and divide both sides of the equation by 3 in order to get x by itself and x = 13

Since x, our first odd integer is 13, our next consecutive odd integer x + 2 would be 15 and x + 4 would be 17.

So 13, 15, and 17 are the 3 consecutive odd integers that add to 45.

25 questions , because they start with 100.  

350-100=250 .  

. 250/10=25

step-by-step explanation:

first take off 100, then what x 10 = 250? that is your answer. (25)

d) by the cross product property, ab^2 = bc multiplied by ad

step-by-step explanation:

we are given

in the given triangle abc

angle a is 90° and segment ad is perpendicular to segment bc

we can see that

triangle(abc) and triangle(abd) are similar because they have common side and same angle (90 degree)

so, triangles(abc) and abd are similar

since, they are similar

so, the ratio of their sides must be equal

we get

now, we can cross multiply

and we get

so, this could be step to prove it