Arectangular garden is 7 feet long and 6 feet wide. a second rectangular garden has 3/2 the dimensions of the first garden .what is the percent in change from the first garden to the second garden

125%

Step-by-step explanation:

Given: First Rectangular garden has dimension of 7 feet long and 6 feet wide.

           Second Rectangular garden B has 3/2 the dimensions of the first garden.

Considerdering first garden as "A" and second garden as "B".

First lets find the Area for first rectangular garden.

Formula; Area of rectangle=

Area of Graden A=

∴ Area of Garden A is 42 feet.

Now, finding area of Garden B.

As given second rectangular garden has 3/2 the dimensions of the first garden.

∴ Length=

  Width=

∴ Area of Garden B=

 Area of Garden B= 94.5\ feet

Next, finding percent change from the first garden to the second garden.

Difference in area of garden from A to B=

Percent change=

⇒ Percent change=

Hence, the percent in change from the first garden to the second garden is 125%.

point a is the center of this circle.

the ratio of the lengths of (ef/bc) and (ad/ih) is 2: 1.

step-by-step explanation:

answer: it's a

step-by-step explanation: