What is 1 6\10+ 5 2\10(what is 6\8- 2 4\8)what is 6 6\10- 4 4\10

what is 1 6/10+5 2/10

=16/10 + 52/10 =

16+52   =  68

10              10

6/8-24/8

=6/8-20/8

6-20 =  14

8           8

6 6/10- 4 4/10

=66-44 = 22

10           10

Step-by-step explanation:

1/ if the fraction is mixed number example 2 1/7, it will be 2x7+1 and that will be 15 over 7

2/and if the bottom number example: 2 1/7, 7 is the bottom number and if 2 1/3 (3 is the bottom number) then see what the bottom number have in common example: 7-x1=7

7x2=14

7x3=21

3x1=3

3x2=6

3x3=9

3x4=12

3x5=15

3x6=18

3x7=21

so 21 is 7 and 3 have in common so the bottom number which is now 21 will divide 7 and got 3 and 3 will go on the top number 1 and 21 divide 3 which is 7 will go on the top number 1 and you continue to add your sum or subtract understand or not

is there a picture

step-by-step explanation:

let's add {f(x)=x+1}f(x)=x+1 and {g(x)=2x}g(x)=2x together to make a new function.

f(x)+g(x) =(x+1)+(2x)=x+1+2x=3x+1

let's call this new function hh. so we have:

{h(x)}={f(x)}+{g(x)}{=3x+1}h(x)=f(x)+g(x)=3x+1

we can also evaluate combined functions for particular inputs. let's evaluate function hh above for x=2x=2. below are two ways of doing this.

method 1: substitute x=2x=2 into the combined function hh.

h(x)

h(2)

​    

=3x+1

=3(2)+1

=7

​ since h(x)=f(x)+g(x)h(x)=f(x)+g(x), we can also find h(2)h(2) by finding f(2) +g(2)f(2)+g(2).

first, let's find f(2)f(2):

f(x)

f(2)

​    

=x+1

=2+1

=3

​  

now, let's find g(2)g(2):

g(x)

g(2)

​    

=2x

=2⋅2

=4

​  

so f(2)+g(2)=3+4=\greend7f(2)+g(2)=3+4=7.

notice that substituting x =2x=2 directly into function hh and finding f(2) + g(2)f(2)+g(2) gave us the same answer!