Given: ∆abc, ab = bc, m∠1< 90°. perimeter of ∆abc = 25. difference between two sides is 4. find: ab, bc, ac. can someone me

AB = 7, BC = 7 and AC = 11

Step-by-step explanation:

Let AB = BC = a and CA = b

Now, given that the perimeter of the triangle is 25.

So, 2a + b = 25 (1)

And 4 is the difference between the two unequal sides.

Hence, b - a = 4 (2)  

⇒ 2b - 2a = 8 (3)

Now, solving equations (1) and (3) we get, 3b = 25 + 8 = 33

⇒ b = 11

Hence, from equation (2) we get a = b - 4 = 7

Therefore, AB = 7, BC = 7 and AC = 11 (Answer)

x = ± 6i

step-by-step explanation:

x^2 = -36

take the square root of each side

sqrt(x^2) = sqrt(-36)

we know sqrt(ab) = sqrt(a) sqrt(b)

x = ±sqrt(36) sqrt(-1)

we know that sqrt (-1) = i

x = ± 6i