H(t)=(t+3)^2+5

what is the average rate of change of h over the interval −5≤t≤−1?

0

Step-by-step explanation:

The average rate of change of the function H(t) over the interval can be calculated as

Find H(-5) and H(-1):

Then

and the average rate of change is 0.

54 km / hours

step-by-step explanation:

we need to convert seconds to hours

60 seconds = 1 minutes

60 minutes = 1hour

15 m         60 second   60 minutes

  * *         = 54000 meters/ hour

second     1 minute             1 hour

now we need to convert meters to km

1000 m = 1 km

54000 m       1 km

*   = 54 km / hours

hour               1000m

too many. (jk)

31 v bucks

step-by-step explanation:

since you bought 25 on friday and 6 on tuesday, you can just add them up.

25+6=31

check your work.

31-6=25

i hope this !

-yand3r3