Twenty years ago a small town in texas had a population of 10,000. the population has increased 8% each year since then. what is the current population of this town?
a. the population of this town is approximately 46,609
b. the population of this town is approximately 115,292
c. the population of this town is approximately 256,140
d. the population of this town is approximately 109,856

the answer is C. texas is big that is the only reasonable answer

a. The population of this town is approximately 46,609

Step-by-step explanation:

The population has increased 8% each year since then. This means that the rate at which the population increased is exponential. The formula for determining exponential growth is expressed as

A = P(1+r/n)^nt

Where

A represents the population after n years

n represents the number of years

P represents the initial population.

n represents the number of times the population increased.

r represents the growth rate

Therefore, from the information given

P = 10000

t = 20 years

r = 8/100 = 0.08

n = 1(it increased yearly)

Therefore

A = 10000(1+0.08/1)^1 × 20

A = 10000(1.08)^20

A = 46609

problem:

f(x) = - 2/3x + 5; f(5/2)

substitute 5/2 in for x:

f(5/2) = -2/3(5/2) + 5

simplify the right side:

f(5/2) = -5/3 + 5

f(5/2) = 10/3

f(5/2) = 10/3

i hope this !

what is the original number? you forgot to add it.