Ineed with this problem, can someone ?

By AAS criteria Δ ABC ≅ Δ ADC

Step-by-step explanation:

See the diagram attached.

We have to prove Δ ABC ≅ Δ ADC

Steps :  

Between Δ ABC and Δ ADC

1. CA bisects ∠ BAD, and hence, ∠ CAB = ∠ CAD {Given}

2. ∠ B = ∠ D {Given}

3. Side AC is common to both the triangles.

Hence, by Angle-Angle-Side i.e. AAS criteria Δ ABC ≅ Δ ADC (Proved)

it is true

step-by-step explanation:

all the combinations add up i used   calculator