Isabella saved $15,000 and bought a car that cost $12,700. the insurance for the car
will cost $600 per year. how many full years will isabella be able to pay for car
insurance with her remaining savings?

3 years

Step-by-step explanation:

The following are given in the question:

ISS = Isabella's saving = $15,000

COC = Cost of the car = $12,700

COI = Cost of insurance = $600 per year

Step 1: Calculation of saving remaining after car purchase

SRACP = ISS - COC (1)

Where SRACP denotes saving remaining after car purchase.

Substituting the values above into equation (1), we have:

SRACP = $15,000 - $12,70 = $2,300

Therefore, the saving remaining after car purchase is $2,300.

Step 1: Calculation of the number of full years the remaining saving can cover car insurance

NFYRSCI = SRACP ÷ COI (2)

Where NFYRSCI denotes the number of full years the remaining saving can cover car insurance.

Also, substituting the values above into equation (2), we have:

NFYRSCI = $2,300 ÷ 600 = 3.83 years or 3 full years

Therefore, the number of full years the remaining saving can cover car insurance is just 3 full years.

Note that we are concerned about full years. Therefore, the decimal numbers of 0,83 (i.e. 3.83 - 3 = 0.83) which gives 10 months (i.e. 0.83*12 = 10 months) is not relevant since it is not up to a year.

option c) graph of line going through 1, 4 and 3, 10

step-by-step explanation:

let y equal to margo's coin collection

let x equal to number of years

at the begining x=0, y=1 → point=(x,y)→point=(0,1)

she adds 3 coins per year, then y=1+3x

at x=1, y=1+3(1)=1+3→y=4→point=(x,y)→point=(1,4)

at x=3, y=1+3(3)=1+9→y=10→point=(x,y)→point=(3,10)

the graph of line going through (1, 4) and (3, 10), then the option c is the correct.

step-by-step explanation:

im not sure what the answer is