How much candy at $1.20 a pound should be mixed with candy worth 95¢ a pound in order to obtain a mixture of 50 pounds of candy worth a dollar a pound?

10 pounds of candy worth $1.20 per pound should be mixed with 40 pounds of candy worth 95¢ per pound

Step-by-step explanation:

Let

x ----> pounds of candy worth at $1.20 a pound

y ----> pounds of candy worth at 95¢ a pound

we know that

The pounds of candy worth at $1.20 a pound plus the pounds of candy worth at 95¢ a pound must be equal to 50 pounds of candy worth a dollar a pound

so

The linear equation that represent this situation

----> equation A

----> equation B

solve the system by graphing

Remember that the solution of the system is the intersection point both graphs

using a graphing tool

The solution is the point (10,40)

see the attached figure

therefore

10 pounds of candy worth $1.20 per pound should be mixed with 40 pounds of candy worth 95¢ per pound

current in the circuit at time t is /, then the power delivered to the resistor is

step-by-step explanation: