Question 6(multiple choice worth 1 points) (04.02 mc) a contractor is building a new subdivision on the outside of a city. he has started work on the first street and is planning for the other streets to run in a direction parallel to the first. the second street will pass through (1, 5). find the equation of the location of the second street in standard form.

The equation of the second street is y= -x+6.

Step-by-step explanation:

The graph for the question uploaded below.

The street 1's slope will be the same for street 2 since they are parallel.

To find the slope of the street 1, choose two points from the passing line.

The formula for finding slope,.

and .

Here let us take (0,1) and (1,0).

rise=0-(1). and run =1-0.

rise= -1 and run 1.

.

m= -1.

The line equation is given by y=mx+c.

substitute m value in this equation.

∴y= -x+c.

we know that the point that street 2 pass through is (1,5).

Substitute this point to find the y-intercept c.

5= -1+c.

c=1+5.

c=6.

∴ The equation for the second street is y= -x+6.

r(0,90)(x,y) . t(-5,0)

last option

step-by-step explanation:

∆def to ∆d"e"f"

- rotate 90 counterclockwise degrees

- then translated 5 to the left (x --> x - 5)

answer is the last option

step-by-step explanation:

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