Consider the students in your statistics class as the population and suppose they are seated in four rows of 10 students each. to select a sample, toss a coin. if it comes up heads, you use the 20 students sitting in the first two rows as your sample. if it comes up tails, you use the 20 students sitting in the last two rows as your sample.
a) is it possible to include students sitting in row 3 with students sitting in row 2 in your sample? (pick one)
o yes, it is possible with this described method of selection.
o no, it is not possible with this described method of selection.
o sometimes it is possible with this described method of selections.

No, it is not possible with this described method of selection.

Step-by-step explanation:

According to the method described in the question, you can not pick row2 and row3 at the same time.

Because the coin comes either heads or tails. In case of heads row1 and row2 is selected, in case of tails row 3 and row 4 is selected.

To include students from row2 and row3 in the sample, the coin has to come up heads and tails at the same flip which is impossible.

36/60

36/2=18

60/2=30

18/30

18/3=6

30/3=10

6/10

6/2=3

10/2=5

your final answer would be 3/5 of an

hope this !

(b) 240

step-by-step explanation:

first, we use the pythagorean formula using the given side lengths to find x. then we use x to find the side lengths. then we add the side lengths to find the perimeter.

pythagorean theorem formula:

a^2 + b^2 = c^2

(x - 20)^2 + (x - 40)^2 = x^2

x^2 - 40x + 400 + x^2 - 80x + 1600 = x^2

x^2 -120x + 2000 = 0

(x - 100)(x - 20) = 0

x - 100 = 0 or x - 20 = 0

x = 100 or x = 20

we see that the solution x = 20 must be discarded because it will give a negative side length and a side length of 0. the only valid solution is x = 100.

perimeter = sum of the lengths of the sides

perimeter = x + x - 20 + x - 40

perimeter = 3x - 60

replace x with 100.

perimeter = 3(100) - 60

perimeter = 300 - 60

perimeter = 240