Mathematics, 14.01.2020 00:31 myg21

The caesar cipher has 25 different shifts to try. how many possibilities are there to try in a random substitution cipher

Answers: 1

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Answer from: maribel234

26! or $\approx 4.03\times10^{26}$

Step-by-step explanation:

The Caesar Cipher is an encoding method that shifts alphabets.The random substitution is an encoding method that move each letter of the alphabet randomly to different .

Given : The Caesar Cipher has 25 different shifts to try.

Since the total a letters in the English Alphabet = 26

Then, the number of possibilities in a random substitution cipher = 26!

$=26\times25\times24\times23\times...\times3\times2\times1\\\\=4.03\times10^{26}$

Hence, there are 26! ( or $\approx 4.03\times10^{26}$ ) possibilities to try in a random substitution cipher .

Answer from: Quest

answer:

payment just for service

→

87.12

payment for service including tax

→

94.09

explanation:

service only with 20% tip

→

72.6

(

100

)

87.12

in the opening of the question the word 'service' is associated only with the pretax value.

the closing part of the question asks: how much did she pay for the

service

−−−−−−

so technically the answer is

→

72.6

(

100

)

87.12

however, the intention of the question provider may have been that your answer is to be

87.12

(

100

)

94.09

to 2 decimal places.

payment just for service

→

87.12

payment for service including tax

→

94.09

tony b

mar 21, 2017

answer:

trying to explain it another way

explanation:

service charge

→

72.60

20% tip

100

72.60

14.52

−−−−−−

←

add

87.12

tax

100

87.12

6.97

−−−−−

←

add

94.09

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The caesar cipher has 25 different shifts to try. how many possibilities are there to try in a rando...