Bad gums may mean a bad heart. researchers discovered that 81% of people who have suffered a heart attack has periodontal disease, an inflammation of the gums. only 30% of healthy people have this disease. suppose that in a certain community heart attacks are quite rare, occurring with only 15% probability.

if someone has periodontal disease, what is the probability that he or she will have a heart attack?

0.405 or 40.5%

Step-by-step explanation:

Let event A=having a periodontal disease

event B=having a heart attack

we are given

P(A)=P(having a periodontal disease)=0.30

P(B)=P(having a heart attack)=0.15

P(A/B)=P(have a periodontal disease/have a heart attack)=0.81

P(B/A)=P(have a heart attack/have a periodontal disease)=?

P(A/B)=P(A∩B)/P(B)

P(A∩B)=P(B)*P(A/B)=0.15*0.81=0.1215

P(B/A)=P(A∩B)/P(A)=0.1215/0.3=0.405

There is 40.5% probability that if someone has periodontal disease will have a heart attack.

answer: 0,6

step-by-step explanation:

this would make it the y intercept.

22

step-by-step explanation:

22