What is the value of x in the equation 3x-4y=65, when y=4?

x = 27

Step-by-step explanation:

Given

3x - 4y = 65 ← substitute y = 4

3x - 4(4) = 65, that is

3x - 16 = 65 ( add 16 to both sides )

3x = 81 ( divide both sides by 3 )

x = 27

problem:

f(x) = - 2/3x + 5; f(5/2)

substitute 5/2 in for x:

f(5/2) = -2/3(5/2) + 5

simplify the right side:

f(5/2) = -5/3 + 5

f(5/2) = 10/3

f(5/2) = 10/3

i hope this !

c

step-by-step explanation:

there is vertical asymptote at x = 2 and x = 0

vertical asymptote occurs at the points where the denominator is 0. so we can say that

x = 2 occurs when there is a factor (x-2) in the denominator, and

x = 0 occurs when there is a factor "x" in the denominator

thus, the denominator of the equation would have "x * (x-2)", this is option c only. that's the correct answer.