The height of an object after it is released can be modeled by the function f (x) = negative 16 t squared + v t + s, where t is the number of seconds after the object is released, v is the upward speed in feet per second at release, and s is the starting height in feet. if a quarterback throws a ball from his hand 6 feet in the air at an upward speed of 25 feet per second, how much time does his teammate have to catch the ball?
about 1.45 seconds
about 1.77 seconds
about 3 seconds
about 6 seconds

1.77 seconds.

Step-by-step explanation:

The height of an object after it is released can be modeled by the function f(x) = - 16t² + v t + s, where t is the number of seconds after the object is released, v is the upward speed in feet per second at release, and s is the starting height in feet.

Now, if a quarterback throws a ball from his hand 6 feet in the air at an upward speed of 25 feet per second, then we have to find the time after which his teammate will catch the ball.

So, we can write

0 = - 16t² + 25t + 6

⇒ 16t² - 25t - 6 = 0

Now, using the quadratic formula we can write  

⇒ seconds. (Answer)

{Neglecting the negative root as t can not be negative.}

logv3(x+2)=1

rewrite in exponential form:

logb(x) = y is equal to b^y =x

b = 3, y = 1

now solve for x:

3^1 = x+2)

x = 3-2

x = 1

see the picture for the graph.