Find the angle measuments of a triagle in which one angle measures 10 degress less than twice the second triangle, and the third angle measures 25 degrees more than the second angle.

the first angle is 72.5 degrees.

The second angle is 41.25 degrees.

The third angle is 66.25 degrees

Step-by-step explanation:

Let x represent the size of the first angle.

Let y represent the size of the second angle.

Let y represent the size of the second angle.

one angle measures 10 degress less than twice the second triangle. This means that

x = 2y - 10

the third angle measures 25 degrees more than the second angle. This means that

z = y + 25

The sum of the angles in a triangle is 180 degrees. This means that

x + y + z = 180 - - - - - - - - - - 1

Substituting x = 2y - 10 and z = y + 25 into 1, it becomes

2y - 10 + y + y + 25 = 180

4y + 15 = 180

4y = 180 - 15 = 165

y = 165/4 = 41.25 degrees

x = 2y - 10 = 41.25 × 2 - 10 = 72.5 degrees

z = x + 25 = 41.25 + 25 = 66.25 degrees

sorry i dont know my friend

relating to or denoting a system of numbers and arithmetic based on the number ten, tenth parts, and powers of ten.

step-by-step explanation: