Which of the following are solutions to the equation tan^2x-3=0? check all that apply.
a. -pi/3
b. 2pi/3
c. pi
d. pi/3

A), B) and D)

Step-by-step explanation:

tan²x - 3 = 0

tan²x = 3

tan x = ± √3

If tan x = + √3:

x = π/3 and x = 4π/3

If tan x = - √3:

x = 2π/3 and x = 5π/3

Then, Alternatives A), B) and D are true. C is false.

I hope I've helped you.

the correct answer is d

hope this

m∠cdf = 43° , m∠gdf = 114°, m∠gde = 23°, m∠edh = 23° , m∠cdh = 157°

step-by-step explanation:

since, it is given that de bisects the angle gdh ⇒ de divides the angle gdh into two equal angles.

⇒ m∠gde = m∠edh

⇒ 8·x   - 1 = 6·x + 5

⇒ x = 3

so, m∠gde = 8·x - 1 = 23°

and m∠edh = 23°

now, it is given ∠cde is an straight angle so, m∠cde = 180°

⇒ m∠cdf + m∠fdg + m∠gde = 180°

⇒ 43° + m∠fdg + 23° = 180°

⇒ m∠fdg = 114°

again, m∠cde = m∠cdh + m∠edh = 180°

m∠cdh + 23° = 180°

⇒ m∠cdh = 157°