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The y-intercept for the given graph of a linear function is y=3x-1

y-intercept=3x-1

Step-by-step explanation:

Given that the graph of a linear function passes through the point (2,5) and has slope 3.

That is m=3

Let the point (2,5) be (x,y)

The slope point formula is y=mx+c

To find the y-intercept  y=mx+c

Substitute the point and slope

y=mx+c

5=3(2)+c

5-6=c

c=-1

Therefore y=3x-1 is the y-intercept

Therefore the y-intercept for the given graph of a linear function is y=3x-1

y-intercept=3x-1

x = ±sqrt(10)

step-by-step explanation:

5 - 2x² = -15

subtract 5 from each side

5-5 - 2x² = -15-5

-2x^2   = -20

divide by -2 on each side

-2x^2   /-2= -20/-2

x^2 =10

take the square root on each side

sqrt(x^2 )=±sqrt(10)

x = ±sqrt(10)

check:

5 - 2x² = -15

+sqrt(10)

5 - 2(sqrt(10))² = -15

5 -2(10) = -15

5 -20 = -15

-15 = -15

-sqrt(10)

5 - 2(-sqrt(10))² = -15

5 -2(10) = -15

5 -20 = -15

-15 = -15

(1, –1), (16, –4), (36, –6)

step-by-step explanation:

given that the function is

this can also be written as

we have to graph this function and check which list of points lie on the graph

see attachment for graph:

we find that the points lying are (1,-1) (16,-4) and (36,-6)

since square root is there we find that x can only be posiitve but y can be since square root both positive and negative.