What percent of a present amount of radioactive radium (226ra) will remain after 1200 years? the half life of 226ra is 1599 years.

59.44%

Step-by-step explanation:

Where = mass remaining

=original mass.

t= time

=half life

=1599,  t= 1200, =226,  =?

n= 0.750469

=134.3367amu

percentage of mass remaining = *100%

                                                   = 59.44%

step-by-step explanation:

option c) graph of line going through 1, 4 and 3, 10

step-by-step explanation:

let y equal to margo's coin collection

let x equal to number of years

at the begining x=0, y=1 → point=(x,y)→point=(0,1)

she adds 3 coins per year, then y=1+3x

at x=1, y=1+3(1)=1+3→y=4→point=(x,y)→point=(1,4)

at x=3, y=1+3(3)=1+9→y=10→point=(x,y)→point=(3,10)

the graph of line going through (1, 4) and (3, 10), then the option c is the correct.