Mathematics, 14.01.2020 22:31 goldenhawk239

Express the solution to the recursion nt+1 = ant in terms of the eigenvectors and eigenvalues of a. use de moivre’s theorem to simplify the solution, if appropriate.

a= [2 3
-4 -6]
and n0 =
[1
0]

Answers: 2

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Express the solution to the recursion nt+1 = ant in terms of the eigenvectors and eigenvalues of a. use de moivre’s theorem to simplify the solution, if appropriate. a= [2 3 -4 -6] and n0 = [1 0]

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Another question on Mathematics

Express the solution to the recursion nt+1 = ant in terms of the eigenvectors and eigenvalues of a. use de moivre’s theorem to simplify the solution, if appropriate.

a= [2 3
-4 -6]
and n0 =
[1
0]