Finding an equation of a tangent line in exercise, find an equation of the tangent line to the graph of the function at the given point.
y = e^-2x + x2 , (2 , 1)

Where the slope is and the intercept

Step-by-step explanation:

For this case w ehave the following function and a point givn P(2,1)

In order to find an equation of the tangent line to the graph of the function given at the point P first we need to find the derivat eof our original equation.

And this value represent the slope for our tangent line at the given point, we can replace the value of x and we got:

Now the general equation for the tangent line is given by:

And for this case and if we replace we got:

And if we simplify we got:

Where the slope is and the intercept

constant acceleration- a

constant velocity- c

no velocity or acceleration- b

explanation:

for body moving with a constant acceleration, the rate of change of displacement changes over time. this is proven by the increasing gradient of the curve (a) against time.

a body that is moving at constant velocity covers equal distances over equal periods of time, thus the straight line with a constant gradient c.

a stationary body   covers no displacement as time elapses. thus the flat line with   zero gradient.

the answer is 0.071

good luck! : d