Find four consecutive even integers such that seven times the first exceeds their sum by 18.

i can’t find the answer, i keep on getting 3. : (

10, 12, 14, 16

Step-by-step explanation:

Given: Four consecutive even integers such that seven times the first exceeds their sum by 18.

Lets assume the first number be "x".

As it is even integers

∴ Second consecutive number will be

  Third consecutive number will be

  Fourth consecutive number will be

Now, as given seven times the first exceeds their sum by 18.

∴

solving the equation to find the number.

⇒

Opening parenthesis

⇒

subtracting both side by 4x

⇒

Dividing both side by 3

∴ x= 10.

Hence, subtituting the value x to find four consecutive even integers.

  First number is 10

  Second consecutive number will be = 12

  Third consecutive number will be = 14

  Fourth consecutive number will be = 16

∴ Four consecutive even integers are 10,12,14,16.

answer: it is d

step-by-step explanation:

answer: your answer is a