Arectangular field has a longer side of 100 meters. a diagonally path across the field makes an angle with the shorter side of 50° what is the perimeter of the field to the nearest meter? show all work

  368 m

Step-by-step explanation:

The long side is opposite the 50° angle, and the short side is adjacent. Then the definition of the tangent ratio tells you ...

  Tan = Opposite/Adjacent

  tan(50°) = (100 m)/(short side)

Multiplying by (short side)/tan(50°) we get ...

  short side = 100 m/tan(50°) ≈ 83.9 m

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The perimeter of the field is the sum of side lengths: two times the short side plus two times the long side:

  P = 2(short side + long side) = 2(83.9 m +100 m) = 367.8 m

  P ≈ 368 m

The perimeter of the field is about 368 meters.

step-by-step explanation:

∆abc has the points a(1, 7), b(-2, 2), and c(4, 2) as its vertices. formed with the point d(1, 2) as its third vertex, then ∆abd is triangle.