Determine whether the improper integral converges or diverges, and find the value of each that converges.
∫^[infinity]_-[infinity] x/x^2+1 dx

Converges to 0

Step-by-step explanation:

Given is an improper integral  where a= -infinity, b = infinity and

f

This resembles the above integral where a = -b

f(x) let us check whether odd or even or neither

=-f(x)

Since f(x) is odd function and integral is of the form -a to a by properties of integrals, this value is 0

Hence answer is 0

answer: it's d

step-by-step explanation: