Suppose that 55% of all adults regularly consume coffee, 60% regularly consume carbonated soda, and 45% regularly consumes both coffee and soda. (a) what is the chance a randomly selected adult regularly drinks coffee but doesn't drink soda? (b) what is the probability that a randomly selected adult consumes coffee, soda or both? (c) what is the probability that a randomly selected adult doesn't regularly consume at least one of these two products?

Step-by-step explanation:

Given that 55% of all adults regularly consume coffee, 60% regularly consume carbonated soda, and 45% regularly consumes both coffee and soda.

Let A represent the set for adults who consume coffee, B soda then AB represents both

P(A) = 0.55 , P(B) = 0.60 and P(AB) = 0.45

By addition theory on probability

b)  the probability that a randomly selected adult consumes coffee, soda or both=P(AUB) =

a)  the chance a randomly selected adult regularly drinks coffee but doesn't drink soda=

c)  the probability that a randomly selected adult doesn't regularly consume at least one of these two products

=1-P(AB) = 0.55

step-by-step explanation: