Asquare has its length and width increase by 2 feet and 4 feet respectively so that it is now a rectangle. the perimeter of the new rectangle is 8 feet less than twice the original perimeter. what was the original perimeter? show i'll work the leads answer

Step-by-step explanation:

Let L represent the length of one side of the square.

A Square has its length and width increase by 2 feet and 4 feet respectively so that it is now a rectangle. This means that the length of the new rectangle would be L - 2 and its width would be L - 4

The perimeter of the original square is 4L.

The perimeter of the new rectangle is 8 feet less than twice the original perimeter. This means that

2[(L - 2) + (L + 4) = 4L × 2 - 8

2(L - 2 + L + 4) = 8L - 8

4L + 4 = 8L - 8

8L - 4L = 4 + 8

4L = 12

L = 12/4 = 3

The original perimeter of the square is

3 × 4 = 12 feet

1.4

2.3

step-by-step explanation:

the formula for the constant of variation is

y= kx

divide each side by x

y/x =kx/x

y/x =k

we know a and y

1.   y/x = k

4/1 =4

check the other values to make sure they are the same

8/2 = 4   12/3 =4   and 16/4 =4  

the constant of variation is 4

2.   y/x = k

3/1 =3

check the other values to make sure they are the same

6/2 = 3   9/3 =3   and 12/4 =3  

the constant of variation is 3

14

step-by-step explanation: