Parallelogram defg is transformed to parallelogram vstu.

parallelogram d e f g is reflected diagonally to form parallelogram v s t u.

which statement about the transformation is true?

Ok. I seem to have to say this a lot, but It is hard to answer a question about a graph, if it doesn't come with a graph to answer it with. So next time, please include a picture or a small screenshot of the graph in your question. Thank you.

The answer is option A

Step-by-step explanation:

Since the original figure is DEFG, therefore DEFG is preimage and VSTU is the image because it is the result of the transformation.

So the option A is correct, or

"Parallelogram DEFG is the pre-image because it is not the result of the transformation".

Also, this is the graph you are looking for(down below)

the answer is c.

for continuous functions, they continue in the same pattern and you have to find that pattern kinda like slope

step-by-step explanation:

if u want da anser kill your teeser ifu hav wun