Mathematics, 16.01.2020 05:31 lordcaos066

Aportrait without its frame has a height 1.5 times its width w, in inches. the width of the frame is 3 inches. which of the following is an expression for the area of the framed portrait in terms of w

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Answer from: munch1239

Area = 1.5w^2+15w+36

Step-by-step explanation:

Let the width of portrait be 'w'

Given:

Height of portrait without frame (h) = 1.5 times its width = 1.5w

Width of the frame is 3 inches on all sides.

Area of the framed portrait is the total area of the portrait plus the area of the frame.

The figure representing the above scenario is shown below.

From the figure, area of rectangle ABCD is the area of the framed portrait.

From the figure,

AB = 3 + w + 3 = w + 6

BC = 3 + h + 3 = h + 6 = 1.5w + 6

Now, area of the rectangle ABCD is given as the product of the length AB and width BC. Therefore,

$Area=AB\times BC\\\\Area=(w+6)(1.5w+6)\\\\Area=(w\times 1.5w)+(w\times 6)+(6\times 1.5w)+(6\times 6)\\\\Area=1.5w^2+6w+9w+36\\\\Area=1.5w^2+15w+36$

Therefore, the expression for the area of the framed portrait in terms of the width 'w' is given as:

Area = 1.5w^2+15w+36

Aportrait without its frame has a height 1.5 times its width w, in inches. the width of the frame is

Answer from: gunner20115

The area of the portrait without the frame will be A=13.5=1.5w^2 .

Given information:

A portrait without its frame has a height 1.5 times its width w, in inches.

The width of the frame is 3 inches.

Length of the frame will be,

$l=1.5w\\l=1.5\times 3\\l=4.5$

So, the area of portrait without frame will be,

$A=l\times w\\A=1.5w\times w\\A=1.5w^2\\A=1.5\times 9=13.5=1.5w^2$

Therefore, the area of the portrait without the frame will be A=13.5=1.5w^2 .

For more details, refer to the link:

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Answer from: Quest

step-by-step explanation:

it's 15

What is the length of the unknown leg in the right triangle ?

Answer from: Quest

solution:

we have to construct

∠m nt ≅ ∠p qr

the steps to draw this construction are

step 1: use a compass to draw an arc from point q which intersects the side pq at point a and the side qr at point b.

step 2: draw a segment nt and use the same width of the compass to draw an arc from point n which intersects the segment nt at a point x.

step 3:

step 4: join points n and y using a straightedge.

step 3:

option (d).maintaining the same width of the compass as ab, draw an arc from point x such that it intersects the arc drawn from n in a point y.

to draw congruent angles , 1. width of compasses while drawing two angles should be same i.e from point at which angle has to be drawn, 2.the distance between the two points where the compass intersects the two sides should be same while drawing any two congruent angles.

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Aportrait without its frame has a height 1.5 times its width w, in inches. the width of the frame is...