Snowy's snow cones has a special bubble gum snow cone on sale. the cone is a regular snow cone that has a spherical plece of bubble gum nested at the bottom of the cone. the
radius of the snow cone is 2 inches, and the height of the cone is 3 inches. if the diameter of the bubble gum is 0.5 inches, which of the following can be used to calculate the volume of
the cone that can be filled with flavored ice?
(3.1412273) - 2 (3.1470.252)
(3.141321/2) - (3.1470.25)
• 313.1412? 13) (3,1410.5)
13.14933/2) – 9 (3.1430.5)

tip $2.90

total $17.40

given : the shape of his satellite can be modeled by   where x and y are modeled in inches.

now,the given equation   is a equation of parabola.

here, coefficient of x is positive, hence the parabola opens rightwards.

on comparing this equation with standard equation , we get

in standard equation, coordinates of focus=(0,m)

thus for given equation coordinates of focus=(0,1.5)

step-by-step explanation:

hello, sorry being so rude after all that fighting i found it kind of funny, so as me saying sorry here is an answer!

since the table showed her that   2km = 2000m.

to determine, how many km in 2000m, she would divide by 1000.

= 2000 / 1000 = 2 km.

similarly, for 8000m = 8000 / 1000 = 8 km

cheers to savings

~

your pal papaguy

55.44 inches

step-by-step explanation:

part a. assuming a perfectly linear relationship, we can find the slope from the first two data points.

slope = m = (change in rainfall)/(change in years)

= (61.80 -62.33)/(2005 -2004) = -0.53/1 = -0.53

then the point-slope form of the equation of the line can be written as

y = m(x -h) +k . . . . . m = -0.53, (h, k) = (0, 62.33)

y = -0.53x +62.33 . . . x = years after 2004

part b. in 2017, x = 2017 -2004 = 13. then the predicted rainfall is

y = -0.53·13 +62.33 = 55.44 . . inches

the predicted rainfall in 2017 is 55.44 in.